find both direction & distance Practice Questions Answers Test with Solutions & More Shortcuts

Question : 46

Kishenkant walks \0 kilometres towards North. From there, he walks 6 kilometres towards South. Then, he walks 3 kilometres towards East. How far and in which direction is he with reference to his starting point ?

a) 5 kilometres North-east

b) 5 kilometres West

c) 7 kilometres West

d) 7 kilometres East

Answer: (a)

direction-and-distance-verbal-reasoning

The movement of Kishenkant is as shown in the figure.

(A to B, B to C and C to D).

AC = (AB - BC)

= (10 - 6)km = 4km

Clearly, D is to the North-east of A.

∴ Kishenkant's distance from starting point A

= AD = $√{AC^2 + CD^2}$

= $√{4^2 + 3^2}$ = $√{25}$

= 5km.

So, Kishenkant is 5km to the North-east of his starting point.

Question : 47

Rasik walks 20 m North. Then he turns right and walks 30 m. Then he turns right and walks 35 m. Then he turns left and walks 15 m. Then he again turns left and walks 15 m. In which direction and how many metres away is he from his original position ?

a) 30 metres East

b) 15 metres West

c) 45 metres East

d) 30 metres West

Answer: (c)

direction-and-distance-verbal-reasoning

The movement of Rasik from A to F is as shown in Figure

Since CD = AB + EF, so F lies in the line with A.

∴ Rasik's distance from original position A

= AF = (AG + GF)

= (BC + DE) = (30 + 15)m = 45m

Also, F lies to the East of A

Question : 48

Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point rind in which direction ?

a) 35 metres North

b) 35 metres East

c) 60 metres East

d) 40 metres East

e) None of these

Answer: (b)

direction-and-distance-verbal-reasoning

The movement of Rohit is as shown in Figure

∴ Rohit's distance from starting point A

= AE = (AD + DE)

= (BC + DE) = (20 + 15) = 35m

Also, E is the East of A.

Question : 49

A man leaves for his office from his house. He walks towards East. After moving a distance of 20 m, he turns towards South and walks 10 m. Then he walks 35 m towards the West and further 5 m towards the North. He then turns towards East and walks 15 m. What is the straight distance in metres between his initial and final positions ?

a) 5

b) 0

c) Cannot be determined

d) 10

e) None of these

Answer: (a)

direction-and-distance-verbal-reasoning

 The movement of the man from A to F are as shown in Figure

Clearly, DC = AB + EF.

∴ F is in line with A.

Also, AF = (BC - DE) = 5 m.

So, the man is 5 metres away from his initial position.

Question : 50

Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P ?

a) 10 metres East

b) 20 metres West

c) 10 metres North

d) 10 metres West

e) None of these

Answer: (d)

direction-and-distance-verbal-reasoning

The movement of Sachin is as shown in Figure

(P to B, B to C, C to D and D to Q)

Clearly, the distance of Q from P

= PQ = (DQ - PQ) = (DQ - BC)

= (40 - 30)m = 10m.

Also, Q is to the west of P

∴ Q is 10m West of P.

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